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George Adu-Agyare9/4/2017Mod 1 AP Physics CWe can separate the problem into 2 variables:the weight of the jar (Wj)the weight of the honey (Wh)we know that together, they weigh 750g, so we can write the equation: Wj+Wh=750gWe also know that the same jar two-thirds full weighs 550g, obviously the only variable that would change is Wh.Wj+(2/3)Wh=550gNow we can do an algebraic system of equations. Wj+Wh=750g Wj+(2/3)Wh=550g-_____________________ (1/3)Wh=200g---->Wh=600gNow that we know the weight of the honey, we can solve for the weight of the empty jar in gramsWj+Wh=750gWh=600gWj+600g=750gWj=150gTherefore, the weight of the empty jar is 150g
Wow, now this is what we call an information rich blog. Used cranes Qatar
This is a brilliant writing and very pleased to find this site. I couldn’t discover to much different information on your blog. I will surely be back again to look at some other important posts that you have in future.
ReplyDeleteUsed cranes Qatar
This comment has been removed by the author.
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteGeorge Adu-Agyare
ReplyDelete9/4/2017
Mod 1 AP Physics C
We can separate the problem into 2 variables:
the weight of the jar (Wj)
the weight of the honey (Wh)
we know that together, they weigh 750g, so we can write the equation:
Wj+Wh=750g
We also know that the same jar two-thirds full weighs 550g, obviously the only variable that would change is Wh.
Wj+(2/3)Wh=550g
Now we can do an algebraic system of equations.
Wj+Wh=750g
Wj+(2/3)Wh=550g
-_____________________
(1/3)Wh=200g---->Wh=600g
Now that we know the weight of the honey, we can solve for the weight of the empty jar in grams
Wj+Wh=750g
Wh=600g
Wj+600g=750g
Wj=150g
Therefore, the weight of the empty jar is 150g
Wow, now this is what we call an information rich blog.
ReplyDeleteUsed cranes Qatar